Using pointers in PHP is quite useful at times; but it can also leave you dumbstruck with serious debugging on your hands. Consider this construct:
[code]for ($i = 0; $i < 10; $i++)
{
$p1 = null;
if ($Buffer [$i]['type'] == 'scanthis'])
{
$p1 =& $Buffer [$i]['data'];
}
..
if ($p1 != null)
..
}//for[/code]
This will in effect dereference and overwrite a given [‘data’] array member of $Buffer if [‘scanthis’] evaluates to true. But I still want to use “null” as an indicator to whether or not to do something.
So I replace the above with:
[code]for ($i = 0; $i < 10; $i++)
{
unset ($p1); <--
$p1 = null;
if ($Buffer [$i]['type'] == 'scanthis'])
{
$p1 =& $Buffer [$i]['data'];
}
..
if ($p1 != null)
..
}//for
[/code]
This will destroy $p1, but not what it’s pointing to, and then it sets $p1 to null, just like before.
This is obvious when you look at it, and there are a number of other ways to accomplish what I describe above, but it had me stumped for a while 🙂
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